Explanation

In 1 ^st beverages the ratio of syrup and water is 2\;:\;5\;.
In 2 ^nd beverages the ratio of syrup and water is 6\;:\;10\;.
To find which beverage is sweeter, we must first equate any term of the two ratios.
So,
\rightarrow 2\;:\;5=\large\frac{2}{5}\normalsize=\large\frac{2\times3}{5\times3}\normalsize=\large\frac{6}{15} _{[3x to equal numerator]}
\rightarrow 6\;:\;10=\large\frac{6}{10}\normalsize=\large\frac{6\times1}{10\times1}\normalsize=\large\frac{6}{10} _{[1x to equal numerator]}
So, we can see, in 1 ^st beverage water quantity is more than the 2 ^nd beverage.
\therefore 2 ^nd beverage is sweeter than the 1 ^st beverage.
Ans: 2 ^nd beverage is sweeter.

Another form of this specific math question exists:

1. Two beverages are compared based on their syrup to water ratios: 2:5 and 6:10. Determining which beverage is sweeter is the objective.
2. If one beverage has a syrup to water ratio of 2:5, and another has a ratio of 6:10, which beverage is sweeter in comparison?
3. When comparing two beverages, one has a syrup-to-water ratio of 2:5 and the other has a ratio of 6:10. Which beverage possesses a sweeter taste?