a) 1 ^{st}

b) 2 ^{nd}

c) both

correct answer is: 2^{nd}

#### Explanation

In 1 ^{st} beverages the ratio of syrup and water is 2\;:\;5\;.

In 2 ^{nd} beverages the ratio of syrup and water is 6\;:\;10\;.

To find which beverage is sweeter, we must first equate any term of the two ratios.

So,

\rightarrow 2\;:\;5=\large\frac{2}{5}\normalsize=\large\frac{2\times3}{5\times3}\normalsize=\large\frac{6}{15} _{[3x to equal numerator]}

\rightarrow 6\;:\;10=\large\frac{6}{10}\normalsize=\large\frac{6\times1}{10\times1}\normalsize=\large\frac{6}{10} _{[1x to equal numerator]}

So, we can see, in 1 ^{st} beverage water quantity is more than the 2 ^{nd} beverage.

\therefore 2 ^{nd} beverage is sweeter than the 1 ^{st} beverage.**Ans:** 2 ^{nd} beverage is sweeter.

###### Another form of this specific math question exists:

**Two beverages are compared based on their syrup to water ratios: 2:5 and 6:10. Determining which beverage is sweeter is the objective.****If one beverage has a syrup to water ratio of 2:5, and another has a ratio of 6:10, which beverage is sweeter in comparison?****When comparing two beverages, one has a syrup-to-water ratio of 2:5 and the other has a ratio of 6:10. Which beverage possesses a sweeter taste?**