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Formula use: \left(a-b\right)^3=a^3-3a^2b+3ab^2-b^3
Here, given expression is : mn-m
Now, Find the cubes of :
\left(mn-m\right)^3
\rightarrow\left(mn\right)^3-3.\left(mn\right)^2.m+3.mn.\left(n\right)^2-\left(m\right)^3
\rightarrow m^3n^3-3m^2n^2m+3mnn^2-m^3
\therefore m^3n^3-3m^3n^2+3mn^3-m^3
Ans: m^3n^3-3m^3n^2+3mn^3-m^3\ .
