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Formula use:
\left(a-b\right)^3=a^3-3a^2b+3ab^2-b^3
Here, given expression is : ab-cd
Now, Find the cubes of :
\left(ab-cd\right)^3
\rightarrow\left(ab\right)^3-3.\left(ab\right)^2.cd+3.ab.\left(cd\right)^2-\left(cd\right)^3
\therefore a^3b^3-3a^2b^2cd+3abc^2d^2-c^3d^3
Ans: a^3b^3-3a^2b^2cd+3abc^2d^2-c^3d^3\ .
