a) ₹2115
b) ₹2175
c) ₹2711
d) ₹2715
correct answer is: ₹2715
Explanation
Let, the man whole property was '1'.
The man gave \large\frac{1}{3} part to his son and \large\frac{1}{5} part to his daughter of his property.
\therefore The man total gave \large\left(\frac{1}{3}+\frac{1}{5}\right) part of his property.
\rightarrow \large\left(\frac{5+3}{15}\right) part of his property.
\rightarrow \large\frac{8}{15} part of his property.
So that,
\left(1-\large\frac{8}{15}\right) part of property was left with the man.
\rightarrow \large\left(\frac{15-8}{15}\right) part of the property.
\rightarrow \large\frac{7}{15} part of the property.
Hence,
\large\frac{7}{15} part of the property =₹1267
\therefore 1 or whole property =₹\left(1267\times\large\frac{15}{7}\right)
\rightarrow ₹2715
\therefore ₹2715 was his property.
Ans: His property was ₹2715.
Alternative phrasings for this particular math query are:
- Calculate the total value of a man’s property when he gave 1/3 to his son, 1/5 to his daughter, and had ₹1267 remaining.
- Find out the worth of a man’s property when he distributed 1/3 to his son, 1/5 to his daughter, and had ₹1267 leftover.
- Calculate the total property value when fractions were distributed to a man’s children, with 1/3 to his son, 1/5 to his daughter, and ₹1267 remaining.