correct answer is: d) 234

Explanation

According to the question,
Three successive remainders are provided which are 49,23 and 4.
So, 1 ^st skip the last two digits from the right end of 75118.
\rightarrow This leaves us with 751.
Then, Divide 751 by some number.
\rightarrow We have a remainder of 49.
Next, divide 491 by the same number. _{(bringing down the 1)}
\rightarrow We get 23 as the remainder.
Finally, divide 238 by the same number. _{(bringing down the 8)}
\rightarrow We get 4 as the remainder.
Here,
To find the required divisor, we can use greatest common divisor or (GCD) method.
First, we find the differences between the dividends and remainders.
751-49=702
491-23=468
238-4=234
Now, we find the greatest common divisor (GCD) of 702,468 and 234.
\rightarrow Divide 468 by 234: \left(468\ \div\ 234\ \right) = 2 with a remainder of 0.
\therefore The GCD of 234 and 468 is 234.
\rightarrow Divide 702 by 234: \left(702\ \div\ 234\ \right) = 3 with a remainder of 0.
\therefore The GCD of 234 and 702 is 234.
Therefore, the greatest common divisor of 234,468 and 702 is 234.
So that, the required divisor is 234.
Ans: The number 234 is the divisor that, when dividing 75118, leaves remainders of 49,23 and 4.

1. If dividing 75118 by a certain number results in remainders of 49, 23 and 4 respectively, what is that divisor?
2. Identify the divisor that, upon dividing 75118, results in remainders of 49, 23 and 4 sequentially.
3. What is the divisor when 75118 is divided, resulting in remainders of 49, 23 and 4 successively?