**Explanation**

Here, length of the garden is 60 m.

Breadth of the garden is 40 m.

\therefore Area of the rectangular garden is = \left(length\ \times\ breadth\right)

=\ \left(60\ m\ \times\ 40\ m\right)

=\ 2400\ sqm

Now, the garden has two ‘5m’ wide path.

\therefore one path length is 60 m & breadth is 5 m _{[garden length = road length]}

\therefore Area of one path is = \left(60\ \times\ 5\right) sqm

= 300 sqm

And, another path length is 40 m & breadth is 5 m _{[garden breadth = road length]}

\therefore Area of another path is = \left(40\ \times\ 5\right) sqm

= 200 sqm

Here, two paths overlap one place and create a square, so we need to subtract that square value of the total area of the path.

We know, area of a square = \left(side\ \times\ side\right)

\therefore subtracting area of the path is = \left(5\ \times\ 5\right) sqm

= 25 sqm.

\therefore Total area of the path is = (sum of two path area – subtracting path area)

= \{\left(300\ +\ 200\right)\ -\ 25\} sqm

= \left(500\ -\ 25\right) sqm

= 475 sqm

According to the question,

1 sqm path paving cost = 80 rupees

\therefore 475 sqm path paving cost = \left(80\ \times475\right) rupees

= 38000 rupees.

Other side,

Area of the garden without path is = \left(2400\ -\ 475\right) sqm

= 1925 sqm.

\therefore The area of each part of the land is = \left(\frac{without\ path\ garden\ area}{4}\right) sqm

= \left(\frac{1925}{4}\right) sqm

= 481.25 sqm**Ans: **The cost of paving the path is 38000 rupees & The area of each part of the land is 481.25 sqm