a) 2\;:\;3
b) 3\;:\;2
c) 5\;:\;2
d) 2\;:\;5
correct answer is: b) 3\;:\;2
Explanation
According to the question,
Ratio of the prices of two houses is 4\;:\;3\;.
And the price of the second house is ₹ 420000.
Let,
First house price is ₹ x.
So,
4\;:\;3\;=\;x\;:\;420000
\rightarrow\large\frac{4}{3}=\frac{x}{420000}
\rightarrow 3x=\left(420000\times4\right)
\rightarrow x=\large\left(\frac{420000\times4}{3}\right)
\rightarrow x=560000 .
So that, first house price is ₹ 560000.
Now, if the price of the first house would have been ₹ 70000 more then,
The price of first house would be ₹ \left(560000+70000\right)
\rightarrow ₹ 630000.
So that,
The new ratio should be :
630000\;:\;420000 or \large\frac{630000}{420000} or \large\frac{63}{42} or \large\frac{3}{2} or 3\;:\;2.
Ans: The ratio of their prices would be 3\;:\;2.
Another method to articulate this particular math query is available:
- The ratio of the prices of two houses is 4 : 3, with the price of the second house being ₹ 420000. Determine the new ratio of their prices if the price of the first house were ₹ 70000 more.
- With the second house priced at ₹ 420000 and a ratio of 4 : 3 for the prices of the two houses, determine the adjusted ratio of their prices if the price of the first house were increased by ₹ 70000
- If the second house is valued at ₹ 420000 and the ratio of the prices of the two houses is 4 : 3, what would be the new ratio of their prices if the price of the first house were raised by ₹ 70000?