correct answer is: b) The second school

Explanation

According to the question,
In the 1 ^st school,
\rightarrow\frac{Examinees\ passed\ with\ grade-A}{Total\ examinees}
\rightarrow\large\frac{100}{150}
\rightarrow\large\frac{2}{3}
In the 2 ^nd school,
\rightarrow\frac{Examinees\ passed\ with\ grade-A}{Total\ examinees}
\rightarrow\large\frac{80}{100}
\rightarrow\large\frac{4}{5}
Now,
\rightarrow\large\frac{2}{3}\normalsize=\large\frac{2\times5}{3\times5}\normalsize=\large\frac{10}{15}
\rightarrow\large\frac{4}{5}\normalsize=\large\frac{4\times3}{5\times3}\normalsize=\large\frac{12}{15}
\therefore\large\frac{10}{15}\normalsize>\large\frac{12}{15}
Ans: The second school got better result getting grade-A, in this year’s Madhyamik examination.

Additional variations of this particular math query are:

1. Out of 150 examinees from the first school in this year’s Madhyamik examination, 100 secured grade-A, whereas 80 out of 100 examinees from the second school achieved the same grade. Determine which school had a more commendable grade-A outcome.
2. In this year’s Madhyamik examination, the first school had 150 examinees, with 100 obtaining grade-A, while the second school had 100 examinees, with 80 achieving grade-A. Establish which school had a better grade-A performance.