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Formula use:
a^3+b^3=\left(a+b\right)^3-3.a.b\left(a+b\right)
Here, given expression is :
\left(x^3+\large\frac{1}{x^3}\right)
\rightarrow\{\left(x+\large\frac{1}{x}\right)^3\normalsize-3.x.\large\frac{1}{x}\normalsize\left(x+\large\frac{1}{x}\right)\normalsize\}
According to the question : x+\large\frac{1}{x}\normalsize = p
\therefore\{\left(p\right)^3-3\times1\times p\}
\therefore p^3-3p
Ans: p^3-3p.
