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Formula use:
\left(a-b\right)^3=a^3-3.a^2.b+3.a.b^2-b^3
Here, given expression is :
27x^3-108x^2y+144xy^2-64y^3
\rightarrow\left(3x\right)^3-3.\left(3x\right)^2.4y+3.3x.\left(4y\right)^2-\left(4y\right)^3
\rightarrow\left(3x-4y\right)^3
Now, put the value of ‘x’ and ‘y’ :
\{\left(3\times4\right)-\left(4\times3\right)\}^3 [x=4,y=3]
\rightarrow\left(12-12\right)^3
\rightarrow\left(0\right)^3
\therefore 0
Ans: 0.
