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Formula use: \left(a-b\right)^3=a^3-3a^2b+3ab^2-b^3
Here, given expression is : x^2-y^2
Now, Find the cubes of :
\left(x^2-y^2\right)^3
\rightarrow\left(x^2\right)^3-3.\left(x^2\right)^2.y^2+3.x^2.\left(y^2\right)^2-\left(y^2\right)^3
\therefore x^6-3x^4y^2+3x^2y^4-y^6
Ans: x^6-3x^4y^2+3x^2y^4-y^6\ .
