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Formula use: \left(a-b\right)^3=a^3-3a^2b+3ab^2-b^3
Here, given expression is : ab-bc
Now, Find the cubes of :
\left(ab-bc\right)^3
\rightarrow\left(ab\right)^3-3.\left(ab\right)^2.bc+3.ab.\left(bc\right)^2-\left(bc\right)^3
\rightarrow a^3b^3-3.a^2b^2.bc+3.ab.b^2c^2-b^3c^3
\therefore a^3b^3-3a^2b^3c+3ab^3c^2-b^3c^3
Ans: a^3b^3-3a^2b^3c+3ab^3c^2-b^3c^3.
