correct answer is: c) 121
formula use: (a-b)²=a² – 2.a.b + b²

EXPLANATION

4(m+n)^2 – 12(m+n)p + 9p^2
\rightarrow \{2(m+n)\}^2 – 2. \{2(m+n)\}.(3p) + (3p)^2
\rightarrow \{2(m+n) - (3p)\}^2
Put the value of m =\ -1,\ n =\ 2,\ p =\ -3
\{2(m+n)\ -\ (3p)\}^2
\rightarrow\{2(-1 + 2) – (3 \times\ -3)\}^2
\rightarrow\{\left(2\times1\right)+\ 9\}^2
\rightarrow\ \left(2\ +\ 9\right)^2
\rightarrow{11}^2
\therefore\ 121
Ans : The value of 4(m+n)^2 – 12(m+n)p + 9p^2 is 121.