Explanation

8 kg of stainless steel is required 560 gm chromium
\therefore 1 kg of stainless steel is required =\large\frac{560}{8} gm chromium
\therefore 15 kg of stainless steel is required =\large\left(\frac{560\times15}{8}\right) gm chromium
\rightarrow 1050 gm chromium
Ans: 1050 gm of chromium required to make 15 kg stainless steel.

Another way, Rules of Three Method

Here, Chromium and Stainless Steel are Directly Proportional.
\therefore\;8\;:\;15\;:\;:\;560\;:\;x
\rightarrow\large\frac{8}{15}=\frac{560}{x}
\rightarrow 8x=560\times15
\rightarrow x=\large\frac{560\times15}{8}
\rightarrow x=1050 gm
Ans: 1050 gm of chromium required to make 15 kg stainless steel.

Additional variations of this particular math query are:

1. If 560 gm of chromium is needed to make 8 kg of stainless steel, how much chromium is required to make 15 kg of stainless steel?
2. How many grams of chromium are needed to produce 15 kg of stainless steel if 560 gm of chromium is required for 8 kg?
3. If 560 gm of chromium is used to make 8 kg of stainless steel, how much chromium is needed to produce 15 kg of stainless steel?
4. Suppose 560 gm of chromium is necessary to make 8 kg of stainless steel. How much chromium is required to make 15 kg of stainless steel?