Explanation

First, we find the LCM of 12,15,18,24 and 36.
The LCM of 12,15,18,24 and 36 is :
2\times2\times3\times3\times5\times2=360
Now, to get 5 as remainder in each case, we need to add 5 to the LCM.
\therefore The required least number is :\left(360+5\right)=365
Ans: 365 is the least number, which when divided by 12,15,18,24 and 36 will leave 5 as remainder in each case.

This particular math question can also be formulated in the following manner:

1. What is the smallest number that, when divided by 12, 15, 18, 24 and 36, leaves a remainder of 5 in each case?
2. Find the least positive number that, when divided by 12, 15, 18, 24 and 36, results in a remainder of 5 for each divisor.
3. What is the smallest whole number that, upon division by 12, 15, 18, 24 and 36, gives a remainder of 5 in each division?