a) ₹x
b) ₹100x
c) ₹\left(\frac{100}x\right)
d) ₹\left(\large\frac{100}{x^2}\right)
correct answer is: d) ₹\left(\large\frac{100}{x^2}\right)
Explanation
Here ‘a sum’ means ‘principal’.
According to the question,
Principle(p) = ?
Rate(r) = x %
Time(t) = x years
S.I. = ₹ x
So, We know, S.I. =\large\frac{p\times t\times r}{100}
\rightarrow ₹x=\left(\large\frac{p\times x\times x}{100}\right)
\rightarrow px^2=₹100x [cross multiply]
\rightarrow p=₹\large\frac{100x}{x^2}
\therefore Sum will be =₹\large\frac{100x}{x^2}
Ans: Sum will be =₹\large\frac{100x}{x^2}
Another method to articulate this particular math query is available:
- How much principal sum will yield ₹x in simple interest at x% per annum for x years?
- Calculate the principal amount needed to generate ₹x in simple interest at x% per annum for x years.
- Find the sum required to earn ₹x in simple interest at an annual rate of x% for x years.
- Determine the principal sum that results in ₹x as simple interest over x years at an interest rate of x% per annum.
- What is the initial amount needed to accrue ₹x in simple interest with an interest rate of x% per annum for x years?