Explanation

Here,
Rate = 10 %
Let, Principal = ₹ 'x'
Time = ‘t’ years
According to the question,
Simple Interest is =₹\left(x\times0.125\right)
So that, S.I. =\left(\frac{p\ \times\ r\ \times\ t}{100}\right)
\rightarrow\left(x\times0.125\right)=\left(\frac{x\times10\times t}{100}\right)
\rightarrow\left(\frac{x\times125}{1000}\right)=\left(\frac{10xt}{100}\right) _{[remove decimal]}
\rightarrow\frac{125x}{10}=10xt _{[divide denominator]}
\rightarrow100xt=125x _{[cross multiply]}
\rightarrow t=\frac{125x}{100x}
\rightarrow t=1\frac{1}{4}
\therefore The time would be 1\frac{1}{4} years
Ans: 1 \frac{1}{4} years.

Another variant of this particular question is:
1.Calculate the time required for the simple interest on a sum to be 0.125 times the principal at a 10% per annum interest rate.
2.In how many years will the simple interest on a certain sum be 0.125 times the principal with a 10% per annum interest rate?
3.Determine the time it takes for the simple interest on a sum to reach 0.125 times the principal at an annual interest rate of 10%.
4.Find the duration needed for the simple interest on a specific sum to be 0.125 times the principal at a 10% per annum interest rate.
5.If the interest rate is 10% per annum, how much time is required for the simple interest on a sum to become 0.125 times the principal?