Correct answer is: a) 56 : 48 : 9

Explanation

Here, given ratios are :
A\;:\;B\;=\;7\;:\;6
B\;:\;C\;=\;16\;:\;3
So, find the A\;:\;B\;:\;C we need to multiply the terms :
A\times B=7\times16=112
B\times B=16\times6=96
B\times C=6\times3=18
\therefore A\;:\;B\;:\;C\;=\;112\;:\;96\;:\;18
Or, 56\;:\;48\;:\;9 _{[simplify, divide by 2]}
Ans: A\;:\;B\;:\;C\;=\;56\;:\;48\;:\;9\;.

There are different versions of this math question:

1. Given that A:B = 7:6 and B:C = 16:3, determine the value of A:B:C.
2. If the ratio of A to B is 7:6 and the ratio of B to C is 16:3, what is the ratio of A to B to C?
3. If the ratio of A to B is 7:6 and the ratio of B to C is 16:3, what is the combined ratio of A:B:C?