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Formula use: \left(a-b\right)^3=a^3-3a^2b+3ab^2-b^3
Here, given expression is : x-2
Now, Find the cubes of :
\left(x-2\right)^3
\rightarrow\left(x\right)^3-3.\left(x\right)^2.2+3.x.\left(2\right)^2-\left(2\right)^3
\therefore x^3-6x^2+12x-8
Ans: x^3-6x^2+12x-8\ .
