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Formula use: \left(a-b\right)^3=a^3-3a^2b+3ab^2-b^3
Here, given number is : 99
Now, Find the cubes of :
\left(100-1\right)^3
\rightarrow\left(100\right)^3-3.\left(100\right)^2.1+3.100.\left(1\right)^2-\left(1\right)^3
\rightarrow 1000000-30000+300-1
\rightarrow 1000300-30001
\therefore 970299
Ans: 970299\ .
