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Formula use: \left(a-b\right)^3=a^3-3a^2b+3ab^2-b^3
Here, given expression is : 2x-3y
Now, Find the cubes of :
\left(2x-3y\right)^3
\rightarrow\left(2x\right)^3-3.\left(2x\right)^2.3y+3.2x.\left(3y\right)^2-\left(3y\right)^3
\therefore{8x}^3-36x^2y+54xy^2-27y^3
Ans: {8x}^3-36x^2y+54xy^2-27y^3\ .
