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Formula use:
a^3-b^3=\left(a-b\right)\left(a^2+ab+b^2\right)
Given expression is: {27a}^3b^3-{64c}^3d^3
Factorize
{27a}^3b^3-{64c}^3d^3
\rightarrow\left(3ab\right)^3-\left(4cd\right)^3
\therefore\left(3ab-4cd\right)\left(9a^2b^2+12abcd+16c^2d^2\right)
Ans: \left(3ab-4cd\right)\left(9a^2b^2+12abcd+16c^2d^2\right)
