Notice: Function _load_textdomain_just_in_time was called incorrectly. Translation loading for the rank-math domain was triggered too early. This is usually an indicator for some code in the plugin or theme running too early. Translations should be loaded at the init action or later. Please see Debugging in WordPress for more information. (This message was added in version 6.7.0.) in /home/u852334439/domains/sciencesparkle.com/public_html/wp-includes/functions.php on line 6114
Calculate the time in which 5000 would become 5500 at

Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In
Continue with Facebook
Continue with Google
or use

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here
Continue with Facebook
Continue with Google
or use

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

Please type your username.

Please type your E-Mail.

Please choose an appropriate title for the question so it can be answered easily.

Please choose the appropriate section so the question can be searched easily.

Please choose suitable Keywords Ex: question, poll.

Browse
Type the description thoroughly and in details.

Choose from here the video type.

Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs".

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

Science Sparkle

Science Sparkle Logo Science Sparkle Logo

Science Sparkle Navigation

  • Home
  • Blog
  • All Questions
  • About Us
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Blog
  • All Questions
  • About Us
  • Contact Us
Home/ Questions/Q 513
Next

Science Sparkle Latest Questions

Science Sparkle
  • 0
Science Sparkle
Asked: 1 year ago2024-02-07T00:44:38+05:30 2024-02-07T00:44:38+05:30In: Interest

Calculate the time in which 5000 would become 5500 at an interest rate of 8% per annum.

  • 0

a) 1 year 3 months

b) 1 year 4 months

c) 1 year 5 months

d) 1 year 6 months

correct answer is: a) 1 year 3 months

Explanation

Here,
Principal (p) = ₹ 5000
Amount = ₹ 5500
S.I. = (Amount – Principal)
Or, S.I. =₹\left(5500-5000\right) or ₹ 500
Rate (r) = 8 % p.a.
Let, Time = ‘t’ years
We know, S.I. =\frac{p\ \times\ t\ \times\ r}{100}
\rightarrow500=\frac{5000\times t\times8}{100}
\rightarrow40000t=50000 [cross multiply]
\rightarrow t=\frac{50000}{40000}
\rightarrow t=1.25
\therefore The time is 1.25 years or 1 years 3 months.
Ans: The time it would take for 5000 to become 5500 at an interest rate of 8% per annum is 1 year and 3 months.

Another way to phrase this particular query is:
1. Determine the duration required for an amount of Rs 5000 to grow to Rs 5500 at an annual interest rate of 8%.
2. Calculate the time it takes for Rs 5000 to reach Rs 5500 at an interest rate of 8% per annum.
3. Find out in how many years Rs 5000 will become Rs 5500 with an 8% per annum interest rate.
4. Calculate the time it takes for an investment of Rs 5000 to grow to Rs 5500 with an annual interest rate of 8%.
5. What is the period needed for Rs 5000 to accumulate to Rs 5500 at a rate of 8% per annum?

  • 00
  • 23
  • 0
  • 0
Share
  • Facebook
  • Report
Leave an answer

Leave an answer
Cancel reply

Browse

Sidebar

Ask A Question

Questions Categories

Algebraic Expression
139Questions
, 0Followers
Ratio & Proportion
139Questions
, 0Followers
Interest
139Questions
, 0Followers
Number System
139Questions
, 0Followers
HCF and LCM
46Questions
, 0Followers
Fraction
46Questions
, 0Followers
Rule of Three
25Questions
, 0Followers
Unitary Method
25Questions
, 0Followers
Speed, Time & Distance
25Questions
, 0Followers
Percentage
25Questions
, 0Followers
Area & Perimeter
25Questions
, 0Followers
Linear Equations
25Questions
, 0Followers
Square & Cube Root
25Questions
, 0Followers
Simplification
25Questions
, 0Followers
Profit & Loss
3Questions
, 0Followers
Probability
3Questions
, 0Followers
Clock & Calendar
3Questions
, 0Followers
Volume & Surface Area
3Questions
, 0Followers
Average
3Questions
, 0Followers
Boats & Streams
3Questions
, 0Followers
Quadratic Equations
3Questions
, 0Followers
Work & Time
0Questions
, 0Followers

Stats

  • Questions 507
  • Answers 0
  • Best Answers 0
  • Users 11
  • Popular
  • Answers
  • ConnieExera

    Yfhwhdiwj jifjiwjdwihfuwfhuw hidjwdjwifheifewo jidjwodjwifh

    • 0 Answers
  • Science Sparkle

    A train running at 2/5 of its own speed reached ...

    • 0 Answers
  • Science Sparkle

    At 3 o’clock Ram has completed 2/5 of his journey, ...

    • 0 Answers

Related Questions

  • The simple interest at x% per annum for x years ...

    • 0 Answers
  • Principal = ₹5000, rate = 9% p.a. and time = ...

    • 0 Answers
  • A sum when reckoned at 7 ½% per annum amounts ...

    • 0 Answers
  • Principal = ₹3560, Amount = ₹4521.20 and time = 3 ...

    • 0 Answers
  • A sum of money lent at simple interest amounts to ...

    • 0 Answers

Top Members

ZArVAlyEDQvSC

ZArVAlyEDQvSC

  • 0 Questions
  • 20 Points
Begginer
JOY

JOY

  • 0 Questions
  • 20 Points
Begginer
Credell Panciera

Credell Panciera

  • 0 Questions
  • 20 Points
Begginer

Trending Tags

Algebraic Expression Fraction HCF and LCM Interest Number System Percentage Ratio & Proportion Rule of Three Speed, Time & Distance Unitary Method

About Us

  • Privacy Policy
  • About Us
  • Contact Us
  • Terms and Conditions

Explore

  • Home
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Communities
  • Polls
  • Contact Us

© 2024 sciencesparkle.com. All Rights Reserved

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.