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Asked: 2 years agoIn: Interest

A sum of money invested at 8% per annum amounts to ₹12122 in 2 years. What will it amount to in 2 years 8 months at 9% per annum?

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a) ₹ 12758 b) ₹ 12858 c) ₹ 12958 d) ₹ 13158 correct answer is: c) ₹ 12958 Explanation Here,Amounts Rate % p.a.Time yearsWe know, SI And,Amount Amount [put S.I. value] ...

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Asked: 2 years agoIn: Interest

What sum would yield a simple interest of ₹660 in 11 years at 8% p.a. rate of interest?

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a) ₹650 b) ₹700 c) ₹750 d) ₹800 correct answer is: c) ₹750 Explanation To find the principal amount (sum) that would yield a simple interest of ₹660 in 11 years at an annual interest rate of 8%, we can use the ...

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Asked: 2 years agoIn: Number System

Find the greatest number of 5 digits which is exactly divisible by 292.

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a) 99995 b) 99993 c) 99992 d) 99991 correct answer is: c) 99992 Explanation We know, digits greatest number is .If we divide by , we get as a quotient and as a remainder.So that,If ...

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Asked: 2 years agoIn: Interest

Principal = ₹5000, rate = 9% p.a. and time = 146 days. Find the simple interest and the amount.

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a) ₹180 & ₹5180 b) ₹280 & ₹5280 c) ₹100 & ₹5080 d) ₹380 & ₹4180 correct answer is: a) ₹180 & ₹5180 Explanation Here,Principal(P) Rate(R) %Time(T) days or yearsWe know, S.I. S.I. S.I. ...

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Asked: 2 years agoIn: Algebraic Expression

Find HCF and LCM of 25a3b17, 75a25b19c18, and 125a19b28c30

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a) HCF & LCM b) HCF & LCM c) HCF & LCM d) HCF & LCM correct answer is: b) HCF & LCM Explanation We know,HCF = Highest ...

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Asked: 2 years agoIn: HCF and LCM

By what greatest quantity must 7/8 kg, 14/15 kg, and 1 1/20 kg be delivered so that the quotients are integers?

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a) b) c) d) correct answer is: d) Explanation The given quantity is kgLet us 1st find the HCF of or The formula we use to get the HCF of two ...

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Asked: 2 years agoIn: HCF and LCM

What is the least number, which when divided by 12, 15, 18, 24 and 36 will leave 5 as remainder in each case?

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a) b) c) d) correct answer is: b) Explanation First, we find the LCM of and The LCM of and is Now, to get as remainder in each case, ...

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