Explanation

According to the question,
The ratio of the spent money is 2\;:\;4\;:\;3\;:\;2.
And, the total money spent is Rs 132 lac.
Let’s,
First year, amount of money spent is Rs 2x lac.
Second year, amount of money spent is Rs 4x lac.
Third year, amount of money spent is Rs 3x lac.
Fourth year, amount of money spent is Rs 2x lac.
So that,
Amount of total money spent is :
\left(2x+4x+3x+2x\right) lac
\rightarrow 11x lac.
Now,
11x= Rs 132 lac
\rightarrow x= Rs \large\frac{132}{11} lac
\rightarrow x = Rs 12 lac.
So that,
Second year, amount of money spent is Rs 4x lac.
\rightarrow Rs \left(4\times12\right)=48 lac.
And,
Total amount of money spent first and Third year is = Rs \left(2x+3x\right) lac.
\rightarrow Rs \left(2\times12+3\times12\right) lac.
\rightarrow Rs \left(24+36\right) lac.
\rightarrow Rs 60 lac.
Ans: Rs 48 lac was spent on the second year and Rs 60 lac was spent on the first and the third year.

There’s another way to pose this same math question:

1. In the village, the expenditure ratio over the last four years for road construction is 2 : 4 : 3 : 2. Given that the total expenditure over these years amounts to 132 lac, determine the expenditure for the second year and the combined expenditure for the first and third years.
2. Over the last four years, the village has spent money on road construction in the ratio 2 : 4 : 3 : 2. With a total expenditure of 132 lac during this period, ascertain the expenditure for the second year and the total expenditure for the first and third years.