correct answer is: d) 93324

Explanation

To form a four digit number using the digits 2, 3, 4 and 5 without repeating any digit:
\rightarrow There are 4 choices for the thousands place (2, 3, 4 or 5).
\rightarrow Once we have chosen one digit for the thousands place, we have 3 remaining choices for the hundreds place.
\rightarrow After choosing digits for the thousands and hundreds places, we have 2 choices left for the tens place.
\rightarrow Last, only 1 digit remains for the unit’s place.
So, we have \left(4\times3\times2\times1\right)=24 possible numbers.
\therefore These 24 numbers are:
2345, 2354, 2435, 2453, 2534, 2543,
3245, 3254, 3425, 3452, 3524, 3542,
4235, 4253, 4325, 4352, 4523, 4532,
5234, 5243, 5324, 5342, 5423, 5432.

And, sum of these number is = 93324.
Ans: The sum of all four digit numbers formed with the digits 2, 3 and 4, without repeating any digit, is 93324.

Other variants of this particular math question are:

1. What is the sum of all four digit numbers formed by the digits 2, 3, 4 and 5, ensuring each digit appears only once?
2. What is the sum of all four digit numbers formed by the digits 2, 3, 4 and 5, ensuring each digit appears only once?
3. Finding the sum of all distinct four digit numbers created from the digits 2, 3, 4 and 5, without duplication.