a) 71
b) 78
c) 79
d) 80
correct answer is: c) 79
Explanation
If we divide ‘68927’ by ‘93’ then we get:
\left(68927\div93\right)
\rightarrow 741 as a quotient and 14 as a remainder.
Here, 741 is the quotient and the next number of 741 is 742 .
If we multiply the divisor (93) to the next number of the quotient (742) then we get:
\left(93\times742\right)
\rightarrow 69006
Now, if we subtract 68927 from 69006 then we get the least number.
So, the least number is =\left(69006-68927\right)
\rightarrow 79
\therefore 79 is the least number.
Ans: To make 68927 exactly divisible by 93, the least number that must be added is 79.
Another Way
If we divide ‘68927’ by ‘93’ then we get:
\left(68927\div93\right)
\rightarrow 741 as a quotient and 14 as a remainder.
Now, if we subtract the remainder (14) form the divisor (93) , then we get:
\left(93-14\right)
\rightarrow 79
So, 79 is the least number which must be added.
Ans: To make 68927 exactly divisible by 93, the least number that must be added is 79.
This precise question can be conveyed differently as well:
- How to calculate the smallest addition required to make 68927 divisible by 93?
- What number should be added to 68927 to ensure divisibility by 93?
- Finding the minimum addition needed to make 68927 divisible by 93.
- Determining the smallest number to add to 68927 for it to be divisible by 93.