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₹624 was distributed among A, B, C and D. If ‘A’ would receive ₹2 more, ‘B’ would receive ₹6 less, ‘C’ would receive 5 times of his money and ‘D’ would receive 1/4th of his money. How much money did each of them receive?

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Asked: 2 years ago2024-01-27T13:36:45+05:30 2024-01-27T13:36:45+05:30In: Fraction

₹624 was distributed among A, B, C and D. If ‘A’ would receive ₹2 more, ‘B’ would receive ₹6 less, ‘C’ would receive 5 times of his money and ‘D’ would receive 1/4th of his money. How much money did each of them receive?

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a) ‘A’ ₹106, ‘B’ ₹198, ‘C’ ₹400 and ‘D’ ₹20

b) ‘A’ ₹98, ‘B’ ₹400, ‘C’ ₹20 and ‘D’ ₹106

c) ‘A’ ₹400, ‘B’ ₹20, ‘C’ ₹106 and ‘D’ ₹198

d) ‘A’ ₹98, ‘B’ ₹106, ‘C’ ₹20 and ‘D’ ₹400

correct answer is: d) ‘A’ ₹98, ‘B’ ₹106, ‘C’ ₹20 and ‘D’ ₹400

Explanation

Let think that A, B, C and D receive Rs a, b, c and d money respectively.
According to the question,
A receive 2 more = B receive 6 less = C receive 5 times = \frac{1}{4} of D receive.
Let assume that:
The new money receiving is ‘k’ . [here ‘k’ can be any number]
So,
\rightarrow\ a + 2 = k
or, a = k -2
\rightarrow\ b - 6 = k
or, b = k + 6
\rightarrow\ 5c = k
or, c =\large \frac{k}{5}
\rightarrow\large \frac{d}{4}\normalsize = k
or, d = 4k

Therefore,
a + b + c + d = 624
\rightarrow\ (k\ -\ 2)\ +\ (k\ +\ 6)\ +\ \left(\frac{k}{5}\right)\ +\ 4k\ =\ 624
\rightarrow\large \frac{5k\ -\ 10\ +\ 5k\ +\ 30\ +\ k\ +\ 20k}{5}\normalsize = 624 [L.C.M = 5]
\rightarrow\ 31k\ +\ 20\ =\ \left(624\ \times\ 5\right) [cross multiply]
\rightarrow\ 31k + 20 = 3120
\rightarrow\ 31k = (3120 - 20)
\rightarrow\ 31k = 3100
\rightarrow\ k =\large \frac{3100}{31}
\rightarrow\ k = 100

So,
\therefore a = k - 2
\rightarrow\ a\ =\ \left(100\ -\ 2\right)\ = ₹98
\therefore b = k + 6
\rightarrow\ b\ =\ \left(100\ +\ 6\right)\ = ₹106
\therefore c =\large \frac{k}{5}
\rightarrow c =\large \frac{100}{5}\normalsize = ₹20
\therefore d = 4k
\rightarrow d = 4 \times 100 = ₹400
Ans: ‘A’ receives ₹98, ‘B’ receives ₹106, ‘C’ receives ₹20 and ‘D’ receives ₹400.

Another variant of this particular question is:
1) Find the distribution of ₹624 among A, B, C, and D, considering the specified conditions: A gets ₹2 more, B gets ₹6 less, C gets 5 times his share, and D gets 1/4th of his share.
2) What are the individual shares of A, B, C, and D if ₹624 is divided among them, with A receiving ₹2 more, B receiving ₹6 less, C receiving 5 times his share, and D receiving 1/4th of his share?
3) Solve the problem of dividing ₹624 among A, B, C, and D, where A gets ₹2 more, B gets ₹6 less, C gets 5 times his amount, and D gets 1/4th of his amount.
4) Calculate the amounts each person A, B, C, and D receives if ₹624 is distributed among them, considering the given conditions.
5) How to distribute ₹624 among four individuals A, B, C, and D given specific conditions on their shares?

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