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Formula use:
a^3-b^3=\left(a-b\right)\left(a^2+ab+b^2\right)
Given expression is: {216x}^3-{343y}^3
Factorize
{216x}^3-{343y}^3
\rightarrow\left(6x\right)^3-\left(7y\right)^3
\rightarrow\left(6x-7y\right)\{\left(6x\right)^2+6x.7y+\left(7y\right)^2\}
\therefore\left(6x-7y\right)\left({36y}^2+42xy+49y^2\right)
Ans: \left(6x-7y\right)\left({36y}^2+42xy+49y^2\right)
